7/x^2-3x=1/x^2-9

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Solution for 7/x^2-3x=1/x^2-9 equation: 



7/x^2-3x=1/x^2-9

We move all terms to the left:

7/x^2-3x-(1/x^2-9)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2-9)!=0

x∈R



We add all the numbers together, and all the variables

-3x+7/x^2-(1/x^2-9)=0

We get rid of parentheses

-3x+7/x^2-1/x^2+9=0

We multiply all the terms by the denominator


-3x*x^2+9*x^2+7-1=0

We add all the numbers together, and all the variables

9x^2-3x*x^2+6=0

Wy multiply elements

9x^2-3x^3+6=0

We do not support expression: x^3

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